-x^2+10-5x=0

Solution for -x^2+10-5x=0 equation:

-x^2+10-5x=0

We add all the numbers together, and all the variables

-1x^2-5x+10=0

a = -1; b = -5; c = +10;
Δ = b2-4ac
Δ = -52-4·(-1)·10
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{65}}{2*-1}=\frac{5-\sqrt{65}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{65}}{2*-1}=\frac{5+\sqrt{65}}{-2}
$